213. House Robber II

Adjacent houses have a security system connected, and it will automatically contact the police if two adjacent houses were broken into on the same night.

Given an integer array nums representing the amount of money of each house, return the maximum amount of money you can rob tonight without alerting the police.


def rob(nums: List[int]):
                 
    def linear_rob(houses):
       
        H = len(houses)
        max_amounts = [0]*3                  
        max_amount = 0

        for i in range(H):
            j = (i + 3) % 3
            max_amounts[j] = max(max_amounts[j-2] + houses[i], max_amounts[j-3] + houses[i])
            max_amount = max(max_amount, max_amounts[j])  
       
        return max_amount
       
    if len(nums) == 0 or nums is None:
        return 0

    if len(nums) == 1:
        return nums[0]

    return max(linear_rob(nums[:-1]), linear_rob(nums[1:])) 

Comments

Post a Comment

Popular posts from this blog

347. Top K Frequent Elements

Given an integer array  nums  and an integer  k , return  the   k   most frequent elements . You may return the answer in  any order .   Example: Input: nums = [1,1,1,2,2,3], k = 2 Output: [1,2] def topKFrequent ( self , nums : List [ int ], k : int ):             freq = Counter ( nums )         return heapq . nlargest ( k , freq . keys (), key = freq . get )    
Read more

849. Maximize Distance to Closest Person

You are given an array representing a row of  seats  where  seats[i] = 1  represents a person sitting in the  i th  seat, and  seats[i] = 0  represents that the  i th  seat is empty  (0-indexed) . There is at least one empty seat, and at least one person sitting. Alex wants to sit in the seat such that the distance between him and the closest person to him is maximized.  Return  that maximum distance to the closest person . def maxDistToClosest ( self , seats : List [ int ]):                     taken = []         for i , occupied in enumerate ( seats ):         if occupied :             taken . append ( i )         S = len ( seats )     T = len ( taken )                 maxDist = max ( taken [ 0 ], S - taken [- 1 ] - 1 ) ...
Read more

674. Longest Continuous Increasing Subsequence

Given an unsorted array of integers  nums , return  the length of the longest  continuous increasing subsequence  (i.e. subarray) . The subsequence must be  strictly  increasing. A  continuous increasing subsequence  is defined by two indices  l  and  r  ( l < r ) such that it is  [nums[l], nums[l + 1], ..., nums[r - 1], nums[r]]  and for each  l <= i < r ,  nums[i] < nums[i + 1] . def findLengthOfLCIS ( nums : List [ int ]):         ans = start = 0         for i in range ( len ( nums )):         if i and nums [ i ] <= nums [ i - 1 ]:             start = i         ans = max ( ans , i - start + 1 )             return ans      
Read more